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Miscellaneous Exercise · Q24

Q.Find the derivative of (ax2+sin⁡x)(p+qcos⁡x)(ax^2 + \sin x)(p + q\cos x).

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This is a product of two functions, so use the Product Rule (not the Quotient Rule). The derivative is (2ax+cos⁡x)(p+qcos⁡x)−qsin⁡x (ax2+sin⁡x)(2ax+\cos x)(p+q\cos x)-q\sin x\,(ax^2+\sin x).

The expression (ax2+sin⁡x)(p+qcos⁡x)(ax^2+\sin x)(p+q\cos x) is a product of two functions of xx (with a,p,qa,p,q constants), so the Product Rule (uv)′=u′v+uv′(uv)'=u'v+uv' applies.

Step 1 — Identify the factors.

Let u=ax2+sin⁡xu=ax^2+\sin x and v=p+qcos⁡xv=p+q\cos x.

Step 2 — Differentiate each factor.

u′=2ax+cos⁡x,v′=−qsin⁡x.u'=2ax+\cos x,\qquad v'=-q\sin x.

(Here aa is constant, so ddx(ax2)=2ax\frac{d}{dx}(ax^2)=2ax; pp is constant, so its derivative is 00; and ddx(qcos⁡x)=−qsin⁡x\frac{d}{dx}(q\cos x)=-q\sin x.)

Step 3 — Apply the Product Rule.

ddx(uv)=u′v+uv′=(2ax+cos⁡x)(p+qcos⁡x)+(ax2+sin⁡x)(−qsin⁡x),\frac{d}{dx}(uv)=u'v+uv'=(2ax+\cos x)(p+q\cos x)+(ax^2+\sin x)(-q\sin x), …

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