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Q.Find the derivative of xsin⁡xx \sin x from the first principle.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2018Subjective· 4mImportance★★★★★
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Expanding f(x+h)f(x+h) with the sine addition formula and taking h→0h\to0 in the first-principles definition gives sin⁡x+xcos⁡x\sin x + x\cos x — matching the product rule.

Concept: Derivative from first principle

f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x) = \lim_{h\to0}\dfrac{f(x+h)-f(x)}{h}

Here f(x)=xsin⁡xf(x)=x\sin x.

Step 1: Write the difference quotient

f′(x)=lim⁡h→0(x+h)sin⁡(x+h)−xsin⁡xhf'(x) = \lim_{h\to0}\dfrac{(x+h)\sin(x+h)-x\sin x}{h}

Step 2: Expand sin⁡(x+h)=sin⁡xcos⁡h+cos⁡xsin⁡h\sin(x+h)=\sin x\cos h+\cos x\sin h

(x+h)sin⁡(x+h)=xsin⁡xcos⁡h+xcos⁡xsin⁡h+hsin⁡xcos⁡h+hcos⁡xsin⁡h(x+h)\sin(x+h) = x\sin x\cos h + x\cos x\sin h + h\sin x\cos h + h\cos x\sin h

Subtracting xsin⁡xx\sin x and dividing by hh:

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