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Q.Find the derivative of Sin 2xSin\,2x from the First Principle.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2020Subjective· 4mImportance★★★★★
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Apply the first-principles definition f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h} and the sine-difference identity.

Let f(x)=sin⁡2xf(x) = \sin 2x. By definition:

f′(x)=lim⁡h→0sin⁡2(x+h)−sin⁡2xhf'(x) = \displaystyle\lim_{h\to0} \frac{\sin 2(x+h) - \sin 2x}{h}

Using sin⁡A−sin⁡B=2cos⁡(A+B2)sin⁡(A−B2)\sin A - \sin B = 2\cos\left(\dfrac{A+B}{2}\right)\sin\left(\dfrac{A-B}{2}\right) with A=2x+2h, B=2xA=2x+2h,\ B=2x:

sin⁡(2x+2h)−sin⁡2x=2cos⁡(2x+h)sin⁡(h)\sin(2x+2h)-\sin 2x = 2\cos(2x+h)\sin(h)

So:

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