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Q.Using parallelogram law of vectors, derive an expression for the magnitude and direction of the resultant vector.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2022Subjective· 4mImportance★★★★★
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Representing two vectors as adjacent sides of a parallelogram and using simple right-triangle geometry on the diagonal gives both the magnitude and direction formulas for the resultant.

Statement of the parallelogram law: If two vectors P⃗\vec{P} and Q⃗\vec{Q} acting at a point are represented in magnitude and direction by the two adjacent sides of a parallelogram drawn from that point, then their resultant R⃗\vec{R} is represented in magnitude and direction by the diagonal of the parallelogram passing through that same point.

Derivation:

Let P⃗=OA→\vec{P} = \overrightarrow{OA} and Q⃗=OB→\vec{Q} = \overrightarrow{OB} be drawn from point O, with angle θ\theta between them, and complete the parallelogram OACB, so R⃗=OC→\vec{R} = \overrightarrow{OC} is the diagonal.

Drop a perpendicular from C to the extension of OA, meeting it at N. In the parallelogram, AC=OB=QAC = OB = Q, and the angle ∠CAN=θ\angle CAN = \theta (since AC is parallel to OB).

So, AN=Qcos⁡θAN = Q\cos\theta and CN=Qsin⁡θCN = Q\sin\theta.

In right triangle ONC:

OC2=ON2+CN2=(OA+AN)2+CN2=(P+Qcos⁡θ)2+(Qsin⁡θ)2OC^2 = ON^2 + CN^2 = (OA + AN)^2 + CN^2 = (P + Q\cos\theta)^2 + (Q\sin\theta)^2

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