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Q.How is chlorine prepared by Deacon's process? Explain its reactions with Hot Conc. NaOH, H2S and Na2S2O3.
Telangana TsbieTelangana Board of Intermediate Education 2019Subjective· 8mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Deacon's process: 4HCl + O2 --(CuCl2, 723K)--> 2Cl2 + 2H2O; chlorine oxidises H2S to sulphur and thiosulphate to sulphate, and disproportionates in hot conc. NaOH.
Preparation by Deacon's process:
- A mixture of hydrogen chloride gas and air (oxygen) is passed over a cupric chloride (CuCl2) catalyst at about 723 K. HCl is oxidised to chlorine.
- 4HCl(g) + O2(g) --(CuCl2, 723K)--> 2Cl2(g) + 2H2O(g)
Reactions of chlorine:
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With hot concentrated NaOH (disproportionation to chloride and chlorate):
3Cl2 + 6NaOH(hot, conc.) -> 5NaCl + NaClO3 + 3H2O
Here chlorine is simultaneously reduced (to -1 in NaCl) and oxidised (to +5 in NaClO3).
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With hydrogen sulphide (chlorine oxidises H2S, liberating sulphur):
Cl2 + H2S -> 2HCl + S
Chlorine, being a strong oxidising agent, oxidises the sulphide to sulphur.
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