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Q.Find the equations of the tangents to the hyperbola 3x2−4y2=123x^2 - 4y^2 = 12 which are

(i) Parallel and
(ii) Perpendicular to the line y=x−7y = x - 7.
Telangana TsbieTelangana Board of Intermediate Education 2024Subjective· 4mImportance★★★★★
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Use the tangency condition c2=a2m2−b2c^2=a^2m^2-b^2 for y=mx+cy=mx+c on x2a2−y2b2=1\frac{x^2}{a^2}-\frac{y^2}{b^2}=1, with m=1m=1 (parallel case) and m=−1m=-1 (perpendicular case).

Write the hyperbola 3x2−4y2=123x^2-4y^2=12 in standard form (divide by 12):

x24−y23=1\frac{x^2}{4}-\frac{y^2}{3}=1

so a2=4, b2=3a^2=4,\ b^2=3.

A line y=mx+cy=mx+c is tangent to this hyperbola iff c2=a2m2−b2c^2=a^2m^2-b^2.

The given line y=x−7y=x-7 has slope 11.

(i) Parallel (same slope m=1m=1):

c2=4(1)2−3=1⇒c=±1c^2=4(1)^2-3=1 \Rightarrow c=\pm1

Tangents: y=x+1y=x+1 and y=x−1y=x-1.

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