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Q.Derive the expression for couple acting on a electric dipole in a uniform electric field.

Telangana TsbieTelangana Board of Intermediate Education 2019Subjective· 4mImportance★★★★★
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A dipole in a uniform field feels equal and opposite forces on its two charges, forming a couple of torque τ=pEsin⁡θ\tau = pE\sin\theta, tending to align the dipole with the field.

Setup: Consider an electric dipole consisting of charges +q+q and −q-q separated by a distance 2a2a, with dipole moment p=q(2a)p = q(2a), placed in a uniform electric field E⃗\vec{E} making an angle θ\theta with the dipole moment p⃗\vec{p}.

Forces on the dipole:

  • Force on +q+q: F1=qEF_1 = qE, in the direction of E⃗\vec{E}.
  • Force on −q-q: F2=qEF_2 = qE, opposite to E⃗\vec{E}.

Since the field is uniform, F1=F2=qEF_1 = F_2 = qE and the net force on the dipole is zero (the dipole does not translate). However, since the two equal and opposite forces act along different lines (separated by the dipole length), they constitute a couple, producing a net torque.

Derivation of torque: The perpendicular distance between the two lines of action of the forces is 2asin⁡θ2a\sin\theta.

τ=Force×perpendicular distance=qE×(2asin⁡θ)=(q⋅2a)Esin⁡θ\tau = \text{Force} \times \text{perpendicular distance} = qE \times (2a\sin\theta) = (q \cdot 2a)E\sin\theta

Since p=q(2a)p = q(2a): …

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