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Q.Derive the equation for the couple acting on a electric dipole in a uniform electric field.

Telangana TsbieTelangana Board of Intermediate Education 2022Subjective· 4mImportance★★★★★
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A dipole placed in a uniform field experiences equal and opposite forces on its two charges, forming a couple that tends to align the dipole with the field, of magnitude τ=pEsin⁡θ\tau = pE\sin\theta.

Torque on a dipole in a uniform electric field

Consider an electric dipole consisting of charges +q+q and −q-q separated by a distance 2a2a (dipole moment p=q(2a)p = q(2a), directed from −q-q to +q+q), placed in a uniform external electric field E⃗\vec{E}, making an angle θ\theta with the field direction.

Forces:

  • Force on +q+q: qEqE, along the direction of E⃗\vec{E}
  • Force on −q-q: qEqE, opposite to E⃗\vec{E}

Since the forces are equal in magnitude but opposite in direction, and act at different points (separated by 2a2a), they do not produce a net translational force (Fnet=0F_{net}=0), but they form a couple, producing a net torque.

Derivation: The perpendicular distance between the lines of action of the two equal and opposite forces is:

d=2asin⁡θd = 2a\sin\theta

The magnitude of the torque (moment of the couple) is:

τ=Force×perpendicular distance=qE×2asin⁡θ=(q⋅2a)Esin⁡θ=pEsin⁡θ\tau = \text{Force} \times \text{perpendicular distance} = qE \times 2a\sin\theta = (q\cdot 2a)E\sin\theta = pE\sin\theta

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