Q.Derive the equation for the couple acting on a electric dipole in a uniform electric field.
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Torque on a Dipole — From Intuition to the Formula
Imagine a bar magnet placed in a uniform magnetic field. You know that the north pole gets pulled one way and the south pole the opposite way. If the magnet is not aligned with the field, these two equal and opposite forces create a twist — a torque — that tries to rotate the magnet until it lines up with the field. That's the core idea.
The same thing happens with an electric dipole (two equal and opposite charges +q and −q separated by a small distance d) placed in a uniform electric field E. The two charges experience forces in opposite directions, and unless the dipole is already parallel to the field, those forces produce a torque.
Step 1: The Forces on the Two Charges
Let the dipole moment p point from the negative charge to the positive charge, with magnitude p=qd.
In a uniform electric field E:
- The positive charge +q feels a force F+=+qE (in the direction of E).
- The negative charge −q feels a force F−=−qE (opposite to E).
These two forces are equal in magnitude but opposite in direction. They form a couple — a pair of equal, opposite, parallel forces that do not share the same line of action. A couple always produces a pure torque, with no net force.
Step 2: Why a Torque Appears
If the dipole is at an angle θ to the field, the two forces are not along the same line. They are separated by the perpendicular distance between their lines of action. That perpendicular distance is dsinθ, where d is the separation between the charges.
The torque τ due to a couple is:
τ=(force magnitude)×(perpendicular distance between forces)
Here:
- Force magnitude on each charge: F=qE
- Perpendicular distance: dsinθ
So:
τ=(qE)×(dsinθ)=qdEsinθ
But qd=p, the magnitude of the dipole moment. Therefore:
τ=pEsinθ
Step 3: The Vector Form
Torque is a vector — it has a direction. The direction of the torque is perpendicular to both p and E, following the right-hand rule. The complete vector equation is:
τ=p×E
The magnitude is ∣τ∣=pEsinθ, where θ is the angle between p and E.
Step 4: What the Torque Does
- When θ=0∘ (dipole aligned with the field): sin0=0, so τ=0. The dipole is in stable equilibrium — if you nudge it slightly, the torque brings it back.
- When θ=90∘ (dipole perpendicular to the field): sin90∘=1, so torque is maximum: τmax=pE. …
Why this formula?
Torque on a Dipole in a Uniform Electric Field
Let's build this from first principles — understanding why the torque formula is what it is, not just memorizing it.
What is a Dipole?
A dipole consists of two equal and opposite charges +q and −q, separated by a small distance 2a (or d). The dipole moment vector is:
p=q⋅d
where d points from −q to +q, and ∣d∣=2a.
The Physical Situation
Place this dipole in a uniform external electric field E. Uniform means the field has the same magnitude and direction everywhere.
- The +q charge experiences a force: F+=+qE
- The −q charge experiences a force: F−=−qE
These two forces are equal in magnitude but opposite in direction.
Why is there a Torque?
Since the forces are equal and opposite, the net force on the dipole is zero:
Fnet=qE+(−qE)=0
So the dipole won't accelerate linearly. But — crucially — the two forces act at different points in space (the two charges are separated). This creates a couple (a pair of equal, opposite, parallel forces not acting along the same line). A couple always produces a torque (rotational effect).
Deriving the Torque Magnitude
Let the dipole be oriented at an angle θ with respect to the field E.
- The line joining the charges makes angle θ with E.
- The perpendicular distance between the lines of action of the two forces is the "lever arm."
Step 1: The force on each charge is qE.
Step 2: The perpendicular distance between the two forces is:
Lever arm=2asinθ
Why sinθ? Because the separation vector d is at angle θ to E. The component of d perpendicular to E is dsinθ=2asinθ.
Step 3: Torque = Force × Perpendicular distance (for one force about the midpoint):
τ=(qE)×(2asinθ)
Step 4: But q×2a=p, the dipole moment magnitude. So:
τ=pEsinθ
Vector Form — The Full Picture
Torque is a vector. Its direction is given by the right-hand rule: it tends to rotate the dipole toward alignment with the field.
The vector form captures both magnitude and direction:
τ=p×E
- Magnitude: ∣τ∣=pEsinθ (as derived)
- Direction: Perpendicular to both p and E, given by the cross product rule.
--- …
Placing a dipole in a uniform field subjects its two charges to equal and opposite forces qE; because these act along different lines, they form a couple that produces a net torque tending to rotate the dipole into alignment with the field, even though the net force on the dipole is zero. …
A dipole placed in a uniform field experiences equal and opposite forces on its two charges, forming a couple that tends to align the dipole with the field, of magnitude τ=pEsinθ.
Torque on a dipole in a uniform electric field
Consider an electric dipole consisting of charges +q and −q separated by a distance 2a (dipole moment p=q(2a), directed from −q to +q), placed in a uniform external electric field E, making an angle θ with the field direction.
Forces:
- Force on +q: qE, along the direction of E
- Force on −q: qE, opposite to E
Since the forces are equal in magnitude but opposite in direction, and act at different points (separated by 2a), they do not produce a net translational force (Fnet=0), but they form a couple, producing a net torque.
Derivation: The perpendicular distance between the lines of action of the two equal and opposite forces is:
d=2asinθ
The magnitude of the torque (moment of the couple) is:
τ=Force×perpendicular distance=qE×2asinθ=(q⋅2a)Esinθ=pEsinθ
…
- CBSE 2026Set A1 markMCQQ.When an electric dipole p is placed in a uniform electric field E, then at what angle between p and E, the value of torque will be maximum? (A) 0° (B) 45° (C) 90° (D) 180°
›Reveal solutionSolution
The torque on a dipole is τ = pE sinθ, which peaks when the dipole is perpendicular to the field (θ = 90°).
The torque on an electric dipole of moment p in a uniform field E is
τ=pEsinθ …
- CBSE 2025Set 55/4/11 markMCQQ.A bar magnet is initially at right angles to a uniform magnetic field. The magnet is rotated till the torque acting on it becomes one-half of its initial value. The angle through which the bar magnet is rotated is: (A) 30∘ (B) 45∘ (C) 60∘ (D) 75∘
›Reveal solutionSolution
The torque on a magnetic dipole is τ=mBsinθ, maximum when perpendicular (θ=90∘). When torque drops to half its initial value, sinθ=21, giving θ=30∘ — so the magnet rotates through 60∘.
Understanding torque on a magnetic dipole
When a bar magnet (magnetic dipole of moment m) sits in a uniform magnetic field B, it experiences a torque that tries to align it with the field. The magnitude of this torque depends on how misaligned the dipole is:
τ=mBsinθ
where θ is the angle between the magnetic moment vector and the field direction.
The torque is maximum when the dipole is perpendicular to the field (θ=90∘, so sinθ=1), and zero when aligned (θ=0∘). This makes physical sense: the restoring couple is strongest when the magnet is sideways to the field lines.
τ=mBsinθ
Step-by-step solution
1. Identify the initial configuration
The magnet starts "at right angles to a uniform magnetic field," meaning the magnetic moment makes an angle θi=90∘ with the field. The initial torque is:
τi=mBsin90∘=mB
2. Set up the condition after rotation
After rotating the magnet, the torque becomes half the initial value:
τf=2τi=2mB
Let the new angle between the magnetic moment and field be θf. Then:
mBsinθf=2mB
3. Solve for the final angle
Dividing both sides by mB:
sinθf=21
This gives: …
- CBSE 2025Set ANNUAL1 markMCQQ.An electric dipole is placed at an alignment angle of 30° with an electric field of 2×105 NC−1. It experiences a torque equal to 8 Nm. The charge on the dipole if the dipole length is 1 cm is :(a) 5 mC(b) 4 mC(c) 7 mC(d) 8 mC
›Reveal solutionSolution
Computing the dipole moment from τ=pEsinθ and then the charge from p=qd gives q=8 mC.
Working
Torque on a dipole in a uniform field: τ=pEsinθ.
Given τ=8 Nm, E=2×105 NC−1, θ=30°:
p=Esinθτ=(2×105)(0.5)8=1×1058=8×10−5 Cm
…
- CBSE 2023Set ANNUAL1 markMCQQ.Torque acting on electric dipole of dipole moment p⃗ placed in uniform electric field E⃗ is –(a) p⃗ × E⃗(b) p⃗ . E⃗(c) p⃗ × (E⃗ × p⃗)(d) E . (p⃗/p²)
›Reveal solutionSolution
An electric dipole in a uniform field feels equal and opposite forces on its two charges, forming a couple whose torque is the vector cross product of the dipole moment and the field.
Why: For a dipole of charges +q and −q separated by d (dipole moment p=qd) placed in a uniform field E, the force on +q is qE and on −q is −qE — equal, opposite, and (since the field is uniform) acting at different points, so they form a couple with no net force but a net torque.
Steps:
- Torque of a couple = force × perpendicular distance between the lines of action. …
- CBSE 2017Set ANNUAL1 markMCQQ.The torque acting on an electric dipole of dipole moment P placed at an angle 90° to the electric field E will be: (A) PE (B) PE cos θ (C) PE / sin θ (D) Zero
›Reveal solutionSolution
Dipole torque is τ=PEsinθ; at 90∘ this reduces to PE.
An electric dipole of moment P placed in a uniform field E experiences a torque
τ=P×E,∣τ∣=PEsinθ
where θ is the angle between P and E.
Substituting θ=90∘: sin90∘=1, so
τ=PE×1=PE …
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