More Questions · Q9
Q.Ignoring air resistance, for the maximum horizontal range on level ground a projectile should be released at an angle of:
(a) 30 degrees
(b) 45 degrees
(c) 60 degrees
(d) 90 degrees
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Start your 14-day free trial to unlock the full solution →Range is maximum when sin(2θ) is greatest, which happens at θ = 45°, so the answer is (b) 45 degrees.
R = (v² sin(2θ)) / g
where R = horizontal range, v = speed of projection, θ = angle of projection, g = acceleration due to gravity.
For a given speed v, the range depends only on sin(2θ). The sine function reaches its maximum value of 1 when its angle is 90°:
- sin(2θ) is maximum when 2θ = 90°
- θ = 45° …
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