Q.If , then find the least positive integral value of .
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Start your 14-day free trial to unlock the full solution →The key idea is to simplify the complex fraction to , then find the smallest positive integer such that . The least positive integral value of is .
This problem is a classic example of how a complex number expression can be tamed by first simplifying its core. Instead of wrestling with powers of a messy fraction, we reduce the base to its simplest form and then work with powers of that simple result.
The expression looks like a division of two complex numbers. The standard trick is to multiply numerator and denominator by the conjugate of the denominator, which makes the denominator real and lets the fraction collapse to a simple value.
Let's verify this step by step.
- Simplify the base fraction. Multiply numerator and denominator by the conjugate of the denominator, :
Since , the denominator becomes . The numerator expands:
So the whole fraction simplifies to:
Notice both and have the same modulus (), so the quotient has modulus — this is why the simplified fraction turned out to be a number like that lies exactly on the unit circle.
- Rewrite the given equation. The original condition becomes: …
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