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Miscellaneous Exercise · Q9

Q.If 4-digit numbers greater than 5,000 are randomly formed from the digits 0, 1, 3, 5, and 7, what is the probability of forming a number divisible by 5 when,

(i) the digits are repeated?
(ii) the repetition of digits is not allowed?
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A 44-digit number >5000>5000 from {0,1,3,5,7}\{0,1,3,5,7\} needs first digit 55 or 77; divisibility by 55 needs last digit 00 or 55. Excluding 50005000 (which is not >5000>5000): (i) with repetition 3383\dfrac{33}{83};

(ii) without repetition 38\dfrac{3}{8}.

The available digits are {0,1,3,5,7}\{0,1,3,5,7\}. For a 44-digit number to be greater than 50005000, the thousands (first) digit must be 55 or 77. To be divisible by 55, the units (last) digit must be 00 or 55. Note that 50005000 can be written from these digits when repetition is allowed, but 50005000 is not greater than 50005000, so it must be excluded.

(i) Digits repeated

Total numbers >5000>5000: first digit 22 ways (55 or 77); each of the other three places 55 ways; then remove 50005000:

2×5×5×5−1=250−1=249.2\times 5\times 5\times 5-1=250-1=249.

Favourable (also divisible by 55): first digit 22 ways, the two middle places 55 ways each, last digit 22 ways (00 or 55); then remove 50005000:

2×5×5×2−1=100−1=99.2\times 5\times 5\times 2-1=100-1=99.

P=99249=3383.P=\frac{99}{249}=\frac{33}{83}.

(ii) Repetition not allowed

Total numbers >5000>5000: first digit 22 ways, then 4,3,24,3,2 ways for the remaining places (no repeats). 50005000 cannot be formed without repetition, so nothing to exclude: …

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