Skip to content
Exercises · Q6

Q.A school teacher wants to analyse results. Identify the appropriate statistical technique to be used along with its justification for the following cases:

(a) Teacher wants to compare performance in terms of division secured by students in Class XII A and Class XII B where each class strength is same.
(b) Teacher has conducted five unit tests for that class in months July to November and wants to compare the class performance in these five months.
Tripura TbseTextbookSubjective· 4mImportance★★★★★est
13% · 13/97 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

For (a) use an independent two-sample t-test (or Mann-Whitney U if assumptions fail) because we compare two separate groups. For (b) use one-way repeated measures ANOVA (or Friedman test) because the same class is measured repeatedly across five time points.

The core idea here is comparing groups — but the structure of the data determines which statistical tool is appropriate. The key distinction is whether the groups being compared are independent (different sets of students) or related (the same students measured multiple times).


(a) Comparing Class XII A and Class XII B

These are two independent groups — the students in A are different from those in B. The teacher wants to see if the distribution of divisions (First, Second, Third, etc.) differs between the two classes.

The appropriate technique: Chi-square test of independence (for categorical data like division) or, if the teacher has actual marks and wants to compare means, an independent two-sample t-test.

Why this is the right tool:

  • The data is categorical (division secured: First, Second, Third, etc.) — not continuous marks.
  • We have two independent samples (Class A and Class B).
  • The chi-square test checks whether the observed frequencies of divisions in the two classes differ significantly from what we'd expect if the classes were the same.
Watch out

A common mistake is to use a paired t-test here. That would be wrong because the students in A and B are different individuals — there is no natural pairing between them.

Justification: The chi-square test compares observed counts in each division category against expected counts under the null hypothesis that class and division are independent. If the p-value is small, we conclude the two classes have different performance distributions.


(b) Comparing Class Performance Across Five Months

Here, the same class (same set of students) is tested five times — July through November. This is repeated measures on the same group.

The appropriate technique: One-way repeated measures ANOVA (if marks are normally distributed) or Friedman test (non-parametric alternative).

Why this is the right tool:

  • The same subjects are measured multiple times — so observations are not independent. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.