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Q.Identify the major product formed in the following reaction: C6H5–NH2 --CHCl3 / KOH (alcoholic), Δ--> Product

Tripura TbseHigher Secondary (+2 Stage) Examination 2024Subjective· 1mImportance★★★★★
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A primary amine + CHCl3 + alcoholic KOH, heated, is the carbylamine (isocyanide) test/reaction — it converts a 1° amine into a foul-smelling isocyanide.

C6H5NH2 + CHCl3 + 3KOH (alcoholic) --Δ--> C6H5NC + 3KCl + 3H2O

Mechanism outline: alcoholic KOH generates dichlorocarbene from CHCl3; this electrophilic carbene reacts with the amine's nitrogen lone pair, and after loss of two more HCl equivalents (base-mediated), the isocyanide (–NC) group is formed. This reaction is specific to primary amines (aliphat …

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