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Q.If the diagonals of a parallelogram are represented by the vectors d1⃗=2i^−j^+k^\vec{d_1}=2\hat{i}-\hat{j}+\hat{k} and d2⃗=3i^+4j^−k^\vec{d_2}=3\hat{i}+4\hat{j}-\hat{k}, find its area.

Tripura TbseHigher Secondary (+2 Stage) Examination 2025Subjective· 3mImportance★★★★★
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When a parallelogram's diagonals are given as vectors, its area is half the magnitude of their cross product.

Given d⃗1=2i^−j^+k^\vec d_1=2\hat i-\hat j+\hat k and d⃗2=3i^+4j^−k^\vec d_2=3\hat i+4\hat j-\hat k, compute the cross product:

d⃗1×d⃗2=∣i^j^k^2−1134−1∣\vec d_1\times\vec d_2=\begin{vmatrix}\hat i&\hat j&\hat k\\2&-1&1\\3&4&-1\end{vmatrix}

=i^((−1)(−1)−(1)(4))−j^((2)(−1)−(1)(3))+k^((2)(4)−(−1)(3))=\hat i\big((-1)(-1)-(1)(4)\big)-\hat j\big((2)(-1)-(1)(3)\big)+\hat k\big((2)(4)-(-1)(3)\big)

=i^(1−4)−j^(−2−3)+k^(8+3)=−3i^+5j^+11k^.=\hat i(1-4)-\hat j(-2-3)+\hat k(8+3)=-3\hat i+5\hat j+11\hat k.

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