Q.Explain why (CH₃)₃C⁺ is more stable than CH₃C⁺H₂ and C⁺H₃ is the least stable cation.
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Start your 14-day free trial to unlock the full solution →Hyperconjugation — σ(C–H) electrons delocalising into the vacant 2p orbital of the positive carbon — grows with the number of α C–H bonds: has nine, has three, and has none it can use (its own C–H bonds lie perpendicular to the vacant p orbital and cannot overlap with it). Hence .
A carbocation's positively charged carbon is hybridised with an empty 2p orbital perpendicular to the plane of its three σ bonds. Anything that feeds electron density into that empty orbital disperses the positive charge and stabilises the ion.
Hyperconjugation does exactly this. A C–H σ bond on an α carbon (a carbon directly bonded to the charged carbon) can align parallel with the empty p orbital and overlap with it sideways, letting the σ electrons spread onto the electron-deficient centre — the delocalisation drawn in Figure 8.4(a) for the ethyl cation. The more α C–H bonds available, the more such overlaps, and the greater the stabilisation.
Counting the α C–H bonds
- (tert-butyl cation): three methyl groups on the charged carbon supply nine α C–H bonds. Nine overlapping σ bonds spread the charge most effectively — the most stable of the three.
- (ethyl cation): one methyl group supplies three α C–H bonds — much less delocalisation, so noticeably less stable.
- (methyl cation): there is no α carbon; the only C–H bonds are those on the charged carbon itself. These lie in the plane of the carbon, perpendicular to the vacant 2p orbital, so they cannot overlap with it at all. With no hyperconjugative stabilisation available, is the least stable cation. …
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