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Worked Examples · Example 14

Q.Let X = {Ram, Geeta, Akbar} be the set of students of Class XI, who are in school hockey team. Let Y = {Geeta, David, Ashok} be the set of students from Class XI who are in the school football team. Find X ∪ Y and interpret the set

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The union of two sets collects every element that belongs to at least one of them. Here, X ∪ Y = {Ram, Geeta, Akbar, David, Ashok} — the combined list of all Class XI students who play hockey or football (or both).

The core idea: What does "union" really mean?

When we take the union of two sets, we are asking: Who is in at least one of these groups? It doesn't matter if a student plays only hockey, only football, or both — if they appear in either set, they belong to the union.

The symbol ∪\cup (cup) is a visual reminder: it opens upward to "collect" everything from both sets. The opposite, ∩\cap (cap), opens downward to "catch" only what's common.

Watch out

A common mistake is to list a student twice if they appear in both sets. The union is a set, so each element appears exactly once — no duplicates allowed.

Step-by-step solution

1. Write down the given sets clearly

We have:

  • X={Ram,Geeta,Akbar}X = \{\text{Ram}, \text{Geeta}, \text{Akbar}\} — hockey team members
  • Y={Geeta,David,Ashok}Y = \{\text{Geeta}, \text{David}, \text{Ashok}\} — football team members

2. Identify what the union asks for

X∪YX \cup Y means: list every student who is in XX or in YY (or both). The "or" here is inclusive — it's the everyday "and/or" of real life.

3. Start listing elements from the first set

Take every name from XX: Ram, Geeta, Akbar. These are all in the union.

4. Add elements from the second set, skipping repeats

Now take each name from YY:

  • Geeta — already listed, so skip it.
  • David — new, add it.
  • Ashok — new, add it.

5. Write the final set

Collecting everything without duplication:

X∪Y={Ram,Geeta,Akbar,David,Ashok}X \cup Y = \{\text{Ram}, \text{Geeta}, \text{Akbar}, \text{David}, \text{Ashok}\} …

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