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Exercise 1.4 · Q3

Q.If A and B are two sets such that A ⊂ B, then what is A ∪ B ?

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✓ Free question

When one set is fully contained inside another, their union is simply the larger set. Here, since A⊂BA \subset B, the union A∪BA \cup B equals BB.

The idea is straightforward: the union of two sets collects every element that belongs to at least one of them. If every element of AA is already inside BB (that's what A⊂BA \subset B means), then adding AA to BB doesn't bring in anything new. The union is just BB itself.

Let's walk through it step by step.

  1. What the condition A⊂BA \subset B tells us

    The symbol ⊂\subset means AA is a proper subset of BB: every element of AA is also an element of BB, and AA is not equal to BB (though for the union, even if A=BA = B, the result still holds). So for any x∈Ax \in A, we have x∈Bx \in B.

  2. Definition of union

    A∪B={x∣x∈A or x∈B}A \cup B = \{ x \mid x \in A \text{ or } x \in B \}. An element belongs to the union if it's in AA, or in BB, or in both.

  3. What elements can be in A∪BA \cup B?

    • If x∈Bx \in B, then xx is automatically in A∪BA \cup B (by the "or" condition).
    • If x∈Ax \in A, then because A⊂BA \subset B, we also have x∈Bx \in B. So xx is already covered by the previous case. Thus every element of A∪BA \cup B is an element of BB, and every element of BB is an element of A∪BA \cup B. That means A∪B=BA \cup B = B.
  4. A quick check with an example

    Let A={1,2}A = \{1, 2\} and B={1,2,3,4}B = \{1, 2, 3, 4\}. Clearly A⊂BA \subset B. Then A∪B={1,2,3,4}=BA \cup B = \{1, 2, 3, 4\} = B. Works.

Watch out

A common mistake is to think the union must be "bigger" than both sets. But if one set is inside the other, the union is just the larger set — no new elements appear.

Tip

This result is symmetric: if A⊂BA \subset B, then A∩B=AA \cap B = A as well. The smaller set "disappears" into the larger one for union, and the larger one "contains" the smaller for intersection.

✓Final answer

The union A∪BA \cup B is equal to BB.

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