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Exercise 3.3 · Q18

Q.Prove that sin⁡x−sin⁡ycos⁡x+cos⁡y=tan⁡x−y2\dfrac{\sin x - \sin y}{\cos x + \cos y} = \tan\frac{x-y}{2}.

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This identity is proved by applying the sum-to-product formulas for sine and cosine to the left-hand side, which directly simplifies to tan⁡x−y2\tan\frac{x-y}{2}.

The key insight here is that the left-hand side has a sum of sines in the numerator and a sum of cosines in the denominator. When you see expressions like sin⁡A±sin⁡B\sin A \pm \sin B or cos⁡A±cos⁡B\cos A \pm \cos B, the natural tool is the sum-to-product identities. These convert sums into products, and products often cancel or simplify beautifully.

Let’s recall the two identities we need:

sin⁡A−sin⁡B=2cos⁡A+B2sin⁡A−B2\sin A - \sin B = 2 \cos\frac{A+B}{2} \sin\frac{A-B}{2}

cos⁡A+cos⁡B=2cos⁡A+B2cos⁡A−B2\cos A + \cos B = 2 \cos\frac{A+B}{2} \cos\frac{A-B}{2}

Notice the pattern: the first identity gives a product of a cosine and a sine; the second gives a product of two cosines. When we divide them, the common factor 2cos⁡A+B22\cos\frac{A+B}{2} cancels, leaving a ratio of sine to cosine — which is exactly a tangent.

Now let’s apply this step by step.

  1. Apply the sum-to-product formula to the numerator. Set A=xA = x and B=yB = y in sin⁡A−sin⁡B\sin A - \sin B:

sin⁡x−sin⁡y=2cos⁡x+y2sin⁡x−y2\sin x - \sin y = 2 \cos\frac{x+y}{2} \sin\frac{x-y}{2}

  1. Apply the sum-to-product formula to the denominator. For cos⁡A+cos⁡B\cos A + \cos B with A=xA = x, B=yB = y:

cos⁡x+cos⁡y=2cos⁡x+y2cos⁡x−y2\cos x + \cos y = 2 \cos\frac{x+y}{2} \cos\frac{x-y}{2}

  1. Form the fraction and simplify. The left-hand side becomes:

sin⁡x−sin⁡ycos⁡x+cos⁡y=2cos⁡x+y2sin⁡x−y22cos⁡x+y2cos⁡x−y2\frac{\sin x - \sin y}{\cos x + \cos y} = \frac{2 \cos\frac{x+y}{2} \sin\frac{x-y}{2}}{2 \cos\frac{x+y}{2} \cos\frac{x-y}{2}}

The factor 2cos⁡x+y22 \cos\frac{x+y}{2} appears in both numerator and denominator. Provided cos⁡x+y2≠0\cos\frac{x+y}{2} \neq 0 (which would make the original denominator zero anyway), we cancel it:

=sin⁡x−y2cos⁡x−y2= \frac{\sin\frac{x-y}{2}}{\cos\frac{x-y}{2}}

  1. Recognise the definition of tangent. …

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