Skip to content
Exercise 3.3 · Q8

Q.Prove that cos⁡(π+x)cos⁡(−x)sin⁡(π−x)cos⁡(π2+x)=cot⁡2x\dfrac{\cos(\pi+x)\cos(-x)}{\sin(\pi-x)\cos\left(\frac{\pi}{2}+x\right)} = \cot^2 x.

Uttar Pradesh UpmspTextbookSubjective· 3mImportance★★★★★est
23% · 34/150 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Using standard trigonometric identities for allied angles, the expression simplifies to (−cos⁡x)(cos⁡x)(sin⁡x)(−sin⁡x)=−cos⁡2x−sin⁡2x=cot⁡2x\frac{(-\cos x)(\cos x)}{(\sin x)(-\sin x)} = \frac{-\cos^2 x}{-\sin^2 x} = \cot^2 x.

The key to this problem is recognising that each trigonometric function of an allied angle (like π+x\pi + x, π−x\pi - x, or π2+x\frac{\pi}{2} + x) can be rewritten in terms of a simple function of xx, often with a sign change. Once you replace each term, the expression collapses into a ratio of cos⁡2x\cos^2 x to sin⁡2x\sin^2 x, which is exactly cot⁡2x\cot^2 x.

Let’s go through it step by step.

  1. Simplify cos⁡(π+x)\cos(\pi + x)

    The angle π+x\pi + x lies in the third quadrant, where cosine is negative. The reference angle is xx, so cos⁡(π+x)=−cos⁡x\cos(\pi + x) = -\cos x.

    Tip

    A quick way: cos⁡(π+θ)=−cos⁡θ\cos(\pi + \theta) = -\cos\theta is a standard identity — no need to re-derive each time.

  2. Simplify cos⁡(−x)\cos(-x)

    Cosine is an even function: cos⁡(−x)=cos⁡x\cos(-x) = \cos x. This is because the cosine of a negative angle is the same as the cosine of the positive angle.

  3. Simplify sin⁡(π−x)\sin(\pi - x)

    The angle π−x\pi - x is in the second quadrant, where sine is positive. The reference angle is xx, so sin⁡(π−x)=sin⁡x\sin(\pi - x) = \sin x.

  4. Simplify cos⁡(π2+x)\cos\left(\frac{\pi}{2} + x\right)

    Here, π2+x\frac{\pi}{2} + x is in the second quadrant (if xx is acute), where cosine is negative. The sine-cosine co-function identity gives cos⁡(π2+x)=−sin⁡x\cos\left(\frac{\pi}{2} + x\right) = -\sin x. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.