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Intext Questions · 7.6

Q.Give structures of the products you would expect when each of the following alcohol reacts with

(a) HCl−ZnCl2HCl-ZnCl_2
(b) HBr and
(c) SOCl2SOCl_2.
(i) Butan-1-ol
(ii) 2-Methylbutan-2-ol
Uttar Pradesh UpmspTextbookSubjective· 3mImportance★★★★★
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✓ Free question

Each reagent replaces the −OH-OH of the alcohol by a halogen. Butan-1-ol (1 deg) gives 1-chlorobutane / 1-bromobutane / 1-chlorobutane, and 2-methylbutan-2-ol (3 deg) gives 2-chloro-2-methylbutane / 2-bromo-2-methylbutane / 2-chloro-2-methylbutane.

The reagents

  • HClHCl-ZnCl2ZnCl_2 (Lucas reagent): converts −OH-OH to −Cl-Cl. Fast for 3 deg (via a carbocation, SN1S_N1), slow for 1 deg (SN2S_N2).
  • HBrHBr: converts −OH-OH to −Br-Br (1 deg by SN2S_N2, 3 deg by SN1S_N1).
  • SOCl2SOCl_2 (thionyl chloride): converts −OH-OH to −Cl-Cl, with SO2SO_2 and HClHCl escaping as gases -- the cleanest route to the alkyl chloride.

(i) Butan-1-ol -- CH3CH2CH2CH2OHCH_3CH_2CH_2CH_2OH (primary)

  • (a) HClHCl-ZnCl2ZnCl_2: CH3CH2CH2CH2ClCH_3CH_2CH_2CH_2Cl -- 1-chlorobutane
  • (b) HBrHBr: CH3CH2CH2CH2BrCH_3CH_2CH_2CH_2Br -- 1-bromobutane
  • (c) SOCl2SOCl_2: CH3CH2CH2CH2ClCH_3CH_2CH_2CH_2Cl -- 1-chlorobutane

(ii) 2-Methylbutan-2-ol -- CH3-C(CH3)(OH)-CH2CH3CH_3\text{-}C(CH_3)(OH)\text{-}CH_2CH_3 (tertiary)

  • (a) HClHCl-ZnCl2ZnCl_2: CH3-CCl(CH3)-CH2CH3CH_3\text{-}CCl(CH_3)\text{-}CH_2CH_3 -- 2-chloro-2-methylbutane
  • (b) HBrHBr: CH3-CBr(CH3)-CH2CH3CH_3\text{-}CBr(CH_3)\text{-}CH_2CH_3 -- 2-bromo-2-methylbutane
  • (c) SOCl2SOCl_2: CH3-CCl(CH3)-CH2CH3CH_3\text{-}CCl(CH_3)\text{-}CH_2CH_3 -- 2-chloro-2-methylbutane
✓Final answer

Butan-1-ol -> (a) 1-chlorobutane, (b) 1-bromobutane, (c) 1-chlorobutane.

2-Methylbutan-2-ol -> (a) 2-chloro-2-methylbutane, (b) 2-bromo-2-methylbutane, (c) 2-chloro-2-methylbutane.

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