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Question of 87

Q.What happens when (Give chemical equations only):

(i) Acetaldehyde reacts with dil. NaOH?
(ii) Acetone is heated with solid barium hydroxide?
(iii) Formaldehyde reacts with concentrated NaOH solution?
(iv) Acetic acid reacts with ethanol in presence of H2SO4H_2SO_4.
(v) Acetaldehyde reacts with phenyl hydrazine? OR Write short notes on the following:
(i) Kolbe electrolysis
(ii) Aldol condensation
(iii) Rosenmund reduction.
Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2023Subjective· 5mImportance★★★★★
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Five carbonyl reactions (main alternative of this OR): aldol addition of acetaldehyde; aldol (diacetone alcohol) from acetone + Ba(OH)2Ba(OH)_2; Cannizzaro of formaldehyde; esterification of acetic acid; and phenylhydrazone formation from acetaldehyde.

  1. Acetaldehyde with dilute NaOH (aldol reaction): α\alpha-H containing aldehyde self-adds. 2 CH3CHO→dil. NaOHCH3−CH(OH)−CH2−CHO (3-hydroxybutanal)2\,CH_3CHO \xrightarrow{dil.\ NaOH} CH_3-CH(OH)-CH_2-CHO \ (\text{3-hydroxybutanal})
  2. Acetone heated with solid barium hydroxide (aldol reaction): two acetone molecules combine to the β\beta-hydroxy ketone. 2 (CH3)2C=O→Ba(OH)2(CH3)2C(OH)−CH2−CO−CH3 (4-hydroxy-4-methylpentan-2-one, diacetone alcohol)2\,(CH_3)_2C{=}O \xrightarrow{Ba(OH)_2} (CH_3)_2C(OH)-CH_2-CO-CH_3 \ (\text{4-hydroxy-4-methylpentan-2-one, diacetone alcohol})
  3. Formaldehyde with concentrated NaOH (Cannizzaro reaction): having no α\alpha-H it disproportionates. 2 HCHO→conc. NaOHCH3OH+HCOONa2\,HCHO \xrightarrow{\text{conc. } NaOH} CH_3OH + HCOONa (iv) Acetic acid + ethanol with H2SO4H_2SO_4 (Fischer esterification): …

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