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NCERT Exemplar · Q32

Q.Give the structure of 'A' in the following reaction sequence. 4-methyl-2-nitroaniline (an aniline bearing a –CH3 group para to the –NH2 and an –NO2 group ortho to the –NH2) is treated with

(i) NaNO2 + HCl at 273–278 K, then with
(ii) H3PO2 and H2O, giving A.
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The amino group is turned into a diazonium salt and then replaced by hydrogen. Removing –NH2 from 4-methyl-2-nitroaniline leaves –CH3 and –NO2 meta to each other, so A is m-nitrotoluene.

Step 1 – Diazotisation

4-Methyl-2-nitroaniline + NaNO2 + HCl at 273–278 K converts the –NH2 into a diazonium group:

Ar–NH2 → Ar–N2+ Cl− (4-methyl-2-nitrobenzenediazonium chloride).

Step 2 – Deamination with H3PO2

Hypophosphorous acid (H3PO2) in water reduces the diazonium group, replacing –N2+ by –H and releasing N2:

Ar–N2+ + H3PO2 + H2O → Ar–H + N2 + H3PO3 + HCl.

Result …

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