Skip to content
NCERT Exemplar · Q52

Q.How will you bring out the following conversion: p-nitroaniline (an aniline with a –NO2 group para to the –NH2) is to be converted into 3,4,5-tribromonitrobenzene (a benzene ring bearing –NO2 at position 1 and –Br at positions 3, 4 and 5)?

Uttar Pradesh UpmspShort· 3mImportance★★★★★
74% · 80/108 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Bromination of p-nitroaniline installs –Br at the two positions ortho to –NH2 (para is blocked by –NO2). The –NH2 is then converted to a diazonium salt and replaced by –Br (Sandmeyer). The three –Br groups end up at positions 3, 4 and 5 relative to –NO2.

Step 1 – Bromination (directed by –NH2)

In p-nitroaniline (–NH2 at C1, –NO2 at C4), the strongly activating –NH2 directs bromine ortho/para to itself. The para position (C4) is occupied by –NO2, so Br2 substitutes at both ortho positions (C2 and C6):

p-nitroaniline + 2 Br2 → 2,6-dibromo-4-nitroaniline + 2 HBr.

Step 2 – Diazotisation

2,6-Dibromo-4-nitroaniline + NaNO2 + HCl at 273–278 K → the corresponding benzenediazonium chloride (–N2+ at C1).

Step 3 – Sandmeyer (replace –N2+ by –Br)

Warm the diazonium salt with CuBr/HBr: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.