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Question 54 of 55

Q.(a) Define SI unit of current in terms of the force between two parallel current carrying conductors.

(b) Two long straight parallel conductors carrying steady currents IaI_a and IbI_b along the same direction are separated by a distance dd. How does one explain the force of attraction between them? If a third conductor carrying a current IcI_c in the opposite direction is placed just in the middle of these conductors, find the resultant force acting on the third conductor.
Uttar Pradesh UpmspCBSE Class XII Board 2018Subjective· 3mImportance★★★★★
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F/L=μ0I1I2/2πdF/L=\mu_0 I_1I_2/2\pi d; same-direction currents attract; middle wire feels resultant μ0Ic(Ia−Ib)πd\dfrac{\mu_0 I_c(I_a-I_b)}{\pi d} per unit length.

  1. SI unit of current. One ampere is that steady current which, when maintained in each of two infinitely long, straight, parallel conductors of negligible cross-section placed 1 1\,m apart in vacuum, produces a force of 2×10−7 2\times10^{-7}\,N per metre of length between them. This follows from FL=μ0I1I22πd\dfrac{F}{L}=\dfrac{\mu_0 I_1 I_2}{2\pi d} with I1=I2=1 I_1=I_2=1\,A, d=1 d=1\,m, μ0/2π=2×10−7\mu_0/2\pi=2\times10^{-7}.
  2. Force of attraction. Wire aa produces a field Ba=μ0Ia2πdB_a=\dfrac{\mu_0 I_a}{2\pi d} at wire bb. The force on bb is F⃗=IbL⃗×B⃗a\vec F=I_b\vec L\times\vec B_a; for currents in the same direction this force pulls the wires together — hence attraction. Third conductor in the middle. Wire cc (current IcI_c, opposite direction) is at distance d/2d/2 from each. …

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