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Q.When the nature of force between two parallel current carrying conductor becomes attractive and repulsive?

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2018Subjective· 1mImportance★★★★★
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Concept understanding — Force Between Parallel Wires

Force Between Parallel Current-Carrying Wires

Imagine two long, straight wires placed side by side, each carrying an electric current. You already know that a current-carrying wire creates a magnetic field around it. And you know that a wire placed in a magnetic field experiences a magnetic force. So here, each wire sits inside the magnetic field created by the other wire. That is the whole story — each wire feels a force because of the other wire's magnetic field.

The direction of that force — attraction or repulsion — depends on whether the currents flow in the same direction or opposite directions.

The Intuition

Take two wires with currents in the same direction. Use the right-hand thumb rule: for wire 1, the magnetic field lines circle around it. At the location of wire 2, that field points in a particular direction. Now apply the right-hand rule for force on a current-carrying wire (Fleming's left-hand rule works too): the current in wire 2, crossed with the field from wire 1, gives a force toward wire 1. The same reasoning from wire 2's perspective gives a force on wire 1 toward wire 2. So they attract.

If the currents are opposite, the field directions reverse, and the forces point away from each other — they repel.

Tip

A quick memory aid: Same direction → Attract; Opposite direction → Repel. This is the opposite of what you might guess from electric charges, where like charges repel. Don't mix them up.

The Precise Statement

For two long, straight, parallel wires separated by a distance dd, carrying steady currents I1I_1 and I2I_2, the magnitude of the force per unit length on either wire is:

FL=μ0I1I22πd\frac{F}{L} = \frac{\mu_0 I_1 I_2}{2 \pi d}

where μ0=4π×10−7 N/A2\mu_0 = 4\pi \times 10^{-7} \, \text{N/A}^2 is the permeability of free space.

The force is attractive if the currents are in the same direction, repulsive if they are opposite.

Where Does This Formula Come From?

Wire 1 produces a magnetic field at the location of wire 2. The magnitude of that field is:

B1=μ0I12πdB_1 = \frac{\mu_0 I_1}{2 \pi d}

This field is perpendicular to wire 2. The magnetic force on a length LL of wire 2 carrying current I2I_2 in a perpendicular field B1B_1 is:

F=I2LB1F = I_2 L B_1

Substitute B1B_1:

F=I2L⋅μ0I12πdF = I_2 L \cdot \frac{\mu_0 I_1}{2 \pi d}

Divide both sides by LL to get force per unit length:

FL=μ0I1I22πd\frac{F}{L} = \frac{\mu_0 I_1 I_2}{2 \pi d}

That is the entire derivation — two simple steps: field from one wire, then force on the other.

Important

This formula assumes the wires are infinitely long (or at least very long compared to dd) and thin. It gives the force per unit length, which is constant along the wires.

The Definition of the Ampere

This effect is so fundamental that it defines the SI unit of current. One ampere is defined as the constant current which, when flowing through two infinitely long, straight, parallel wires of negligible cross-section placed one metre apart in vacuum, produces a force of exactly 2×10−72 \times 10^{-7} newtons per metre of length between them. …

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