Q.Calculate the charge on the nucleus ${}_{7}N^{14}$ in coulomb.

Showing the 12 most recent of 34 on this concept.

1. CBSE 2026Set 55/3/11 markMCQ
   Q.If $r_1$ and $r_2$ are the radii of atomic nuclei of mass numbers $64$ and $27$ respectively, then the value of $\dfrac{r_1}{r_2}$ is : (A) $1$ (B) $\dfrac{4}{3}$ (C) $\dfrac{3}{4}$ (D) $\dfrac{27}{64}$

   ›Reveal solutionSolution

   Nuclear radius scales as the cube root of mass number: $r \propto A^{1/3}$. Taking the ratio gives $\frac{r_1}{r_2} = \left(\frac{64}{27}\right)^{1/3} = \frac{4}{3}$.

   The size of an atomic nucleus is not arbitrary. Experiments—particularly Rutherford scattering and later electron-scattering studies—revealed that nuclear radius follows a beautiful empirical law that connects it directly to how many nucleons (protons and neutrons) are packed inside.

   The key insight is that nuclear matter has roughly constant density. Think of nucleons as incompressible spheres packed together: if you double the number of nucleons, you double the volume, not the radius. Since volume scales as $r^3$, the radius must scale as the cube root of the number of nucleons.

   $r = r_0 A^{1/3}$

   where $A$ is the mass number (total nucleons) and $r_0 \approx 1.2 \text{ fm}$ is a constant.

   Now let's find the ratio of the two nuclear radii.

   1. Write the radius for each nucleus For the nucleus with mass number $A_1 = 64$:

   $r_1 = r_0 (64)^{1/3}$

   For the nucleus with mass number $A_2 = 27$:

   $r_2 = r_0 (27)^{1/3}$

   2. Form the ratio When we divide $r_1$ by $r_2$, the constant $r_0$ cancels: …

   🔒 Start your 14-day free trial to see the full solution →
2. CBSE 2026Set V11 markMCQ
   Q.An example for isobars is :

   (a) $^{2}_{1}\text{H}$ and $^{3}_{1}\text{H}$

   (b) $^{2}_{1}\text{H}$ and $^{4}_{2}\text{He}$

   (c) $^{198}_{80}\text{Hg}$ and $^{197}_{79}\text{Au}$

   (d) $^{3}_{1}\text{H}$ and $^{3}_{2}\text{He}$

   ›Reveal solutionSolution

   Option (d) $^{3}_{1}\text{H}$ and $^{3}_{2}\text{He}$. …

   🔒 Start your 14-day free trial to see the full solution →
3. CBSE 2026Set ANNUAL1 markMCQ
   Q.If mass number of a nucleus is 'A', then its radius will be -

   (i) $R=R_0A^{1/3}$

   (ii) $R=R_0A^{4/3}$

   (iii) $R=R_0A^{3}$

   (iv) $R=R_0A^{2/3}$

   ›Reveal solutionSolution

   Nuclear radius scales as the cube root of the mass number.

   Experimentally the nuclear radius is found to be $R=R_0A^{1/3}$, where $R_0\approx1.2\times10^{-15}$ m is a constant, consistent with nuclear density …

   🔒 Start your 14-day free trial to see the full solution →
4. CBSE 2026Set A1 markMCQ
   Q.Which of the following are known as nucleons? (A) Only protons (B) Protons and electrons (C) Protons and neutrons (D) Neutrons and electrons

   ›Reveal solutionSolution

   Nucleons = protons + neutrons, the constituents of the nucleus.

   The atomic nucleus is built from two kinds of particle: positively charged protons and electrically neutral neutrons. Together these are called nucleons. Electrons orbit the nuc …

   🔒 Start your 14-day free trial to see the full solution →
5. CBSE 2026Set ANNUAL1 markMCQ
   Q.As compared to 12C atom, 14C atom has

   (a) two extra protons and two extra electrons

   (b) two extra protons but no extra electrons

   (c) two extra neutrons and no extra electrons

   (d) two extra neutrons and two extra electrons

   ›Reveal solutionSolution

   Isotopes of the same element have the same number of protons and electrons but different numbers of neutrons.

   Both $^{12}_{6}C$ and $^{14}_{6}C$ have atomic number $Z = 6$, so both have 6 protons and (as neutral atoms) 6 electrons — these are identical between the two.

   Mass number $A =$ number of protons + neutrons.

   For $^{12}C$: neutrons $= 12 - 6 = 6$.

   For $^{14}C$: neutrons $= 14 - 6 = 8$. …

   🔒 Start your 14-day free trial to see the full solution →
6. CBSE 2026Set ANNUAL1 markMCQ
   Q.The nucleus is approximately spherical in shape. Then the surface area of nucleus having mass number A varies as ____.

   (a) A^2/3

   (b) A^4/3

   (c) A^1/3

   (d) A^5/3

   ›Reveal solutionSolution

   Nuclear radius scales as $R = R_0A^{1/3}$, so the surface area of a (roughly spherical) nucleus, being proportional to $R^2$, scales as $A^{2/3}$.

   Experiments (electron and alpha-particle scattering) show the nuclear radius depends on mass number as

   $R = R_0 A^{1/3}, \quad R_0 \approx 1.2\times10^{-15}\text{ m}$

   This reflects the fact that nuclear density is roughly the same for all nuclei — nuclear volume, $\propto R^3$, is proportional to A (the number of nucleons).

   …

   🔒 Start your 14-day free trial to see the full solution →
7. CBSE 2025Set ANNUAL1 markMCQ
   Q.Which of the following statements is true-

   (a) Proton is a stable particle and neutron is unstable particle.

   (b) Proton is unstable particle and neutron is stable particle.

   (c) Proton and neutron both are stable particles.

   (d) Proton and neutron both are unstable particles.

   ›Reveal solutionSolution

   A free proton is stable (or has an extremely long lifetime); a free neutron is unstable and decays with a mean life of about 15 minutes.

   A free (isolated) proton does not spontaneously decay — its lifetime is, as far as experiments show, effectively infinite (it is stable, or at least stable on cosmological timescales far exceeding the age of the universe). A free neutron, on the other hand, is unstable: it undergoes beta decay,

   $n \rightarrow p + e^- + \bar u_e$ …

   🔒 Start your 14-day free trial to see the full solution →
8. CBSE 2025Set JS1 mark
   Q.Differentiate between isotopes and isobars.

   ›Reveal solutionSolution

   Isotopes = same $Z$, different $A$ (same element). Isobars = same $A$, different $Z$ (different elements).

   Concept. A nucleus is specified by its atomic number $Z$ (number of protons) and mass number $A$ (protons + neutrons).

   Feature	Isotopes	Isobars
   Atomic number $Z$	same	different
   Mass number $A$	different	same
   Number of neutrons	different	different
   Chemical element	same element	different elements
   Example	$^{1}_{1}H,\ ^{2}_{1}H,\ ^{3}_{1}H$	$^{40}_{18}Ar,\ ^{40}_{20}Ca$
   …

   🔒 Start your 14-day free trial to see the full solution →
9. CBSE 2025Set D1 markMCQ
   Q.What is the main difference between isotopes of the same element? (A) Number of protons (B) Number of neutrons (C) Number of electrons (D) Atomic number

   ›Reveal solutionSolution

   Isotopes differ only in neutron number; their proton number (and hence chemical identity) is the same.

   Isotopes are nuclides of the same element. Being the same element means the same atomic number Z (same number of protons), and in a neutral atom the same number of electrons — so their chemistry is identical.

   …

   🔒 Start your 14-day free trial to see the full solution →
10. CBSE 2025Set ANNUAL1 mark
    Q.____________ is credited with the discovery of the neutron.

    ›Reveal solutionSolution

    The neutron was discovered by James Chadwick in 1932, confirming the existence of a neutral nuclear particle predicted earlier by Rutherford.

    James Chadwick discovered the neutron in 1932 by bombarding beryllium with alpha particles and correctly interpreting the resulting neutral, penetrating radiation as a new particle of mass close to the proton's but with no charge …

    🔒 Start your 14-day free trial to see the full solution →
11. CBSE 2025Set ANNUAL1 mark
    Q.How is the radius of the nucleus related to the mass number?

    ›Reveal solutionSolution

    Experiments (electron/alpha scattering) show nuclear radius scales with mass number as R = R0 A^(1/3), consistent with nucleons packed at essentially constant density.

    The empirical relation between nuclear radius R and mass number A is:

    R = R0 A^(1/3)

    where R0 is an approximately constant value, about 1.2 x 10^-15 m (1.2 fm), found from scattering experiments.

    …

    🔒 Start your 14-day free trial to see the full solution →
12. CBSE 2025Set ANNUAL1 mark
    Q.All atoms except ................ contain neutron in their nuclei. (fill in the blank)

    ›Reveal solutionSolution

    The lightest hydrogen isotope, protium, has a nucleus consisting of a single proton and no neutron — every other atom's nucleus contains at least one neutron.

    A nucleus is characterised by mass number $A = Z + N$, where Z is the number of protons and N the number of neutrons. The ordinary hydrogen atom ($^1_1\text{H}$, protium) has $Z = 1$, $A = 1$, so $N = 0$ — its nucleus is a lone proton with no neutron at all. Every other element (starting from helium, $Z=2$) needs at least o …

    🔒 Start your 14-day free trial to see the full solution →