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Q.What do you understand by polarized light? When a third polaroid is rotated between two crossed polaroids, then discuss the change in the intensity of the transmitted light. OR A lamp “50 watt and 100 volt” is to be connected to AC mains of 200 volt 50 Hz. Calculate the capacity of condenser required in series of lamp.

Uttar Pradesh UpmspUP Board (UPMSP) Intermediate 2025Subjective· 5mImportance★★★★★
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Light with E⃗\vec E vibrations in one plane is polarized. Between crossed polaroids, a middle polaroid at angle θ\theta transmits I=I04sin⁡22θI=\tfrac{I_0}{4}\sin^2 2\theta, peaking at θ=45∘\theta=45^\circ. (An OR numerical on a series capacitor is also offered.)

Polarized light. Ordinary light has electric-field vibrations in all directions perpendicular to propagation (unpolarised). Polarized light has its E⃗\vec E-vibrations restricted to one plane. A polaroid passes only the component along its axis (Malus's law: I=I0cos⁡2θI=I_0\cos^2\theta).

Three-polaroid experiment. Let P1P_1 (polariser) and P3P_3 (analyser) be crossed (axes at 90∘90^\circ). Alone, they transmit zero light. Now insert a third polaroid P2P_2 between them, with its axis at angle θ\theta to P1P_1.

  1. After P1P_1: intensity I0I_0 (say), polarized along P1P_1.
  2. After P2P_2 (at angle θ\theta): I2=I0cos⁡2θI_2=I_0\cos^2\theta, now polarized along P2P_2.
  3. P3P_3 is at 90∘90^\circ to P1P_1, hence at (90∘−θ)(90^\circ-\theta) to P2P_2. After P3P_3: I=I2cos⁡2(90∘−θ)=I0cos⁡2θ sin⁡2θ=I04sin⁡22θ.I=I_2\cos^2(90^\circ-\theta)=I_0\cos^2\theta\,\sin^2\theta=\frac{I_0}{4}\sin^2 2\theta.

Discussion as P2P_2 is rotated.

  • θ=0∘\theta=0^\circ or 90∘90^\circ: I=0I=0 (no light — as with just the crossed pair).
  • θ=45∘\theta=45^\circ: I=I04I=\dfrac{I_0}{4} (maximum). …

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