Q.How would you justify the presence of 18 elements in the 5th period of the Periodic Table?
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Start your 14-day free trial to unlock the full solution →The 5th period has 18 elements because it fills the 5s, 4d, and 5p subshells in that order, which together hold exactly 18 electrons (2 + 10 + 6). This follows directly from the Aufbau principle and the (n + ℓ) rule.
The key to understanding period lengths lies in the Aufbau principle — the idea that electrons fill orbitals in order of increasing energy. A period in the periodic table corresponds to the filling of a principal quantum shell (n). But because of orbital overlap (the (n + ℓ) rule), the filling order isn't simply 1s, 2s, 2p, 3s, 3p, etc. For the 5th period, the outermost shell is n = 5, but the filling sequence involves the 4d subshell as well.
Here’s the step-by-step reasoning:
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Identify the starting point. The 5th period begins when the 5s subshell starts filling. This happens after the 4p subshell is complete (which ends the 4th period). So the first element of period 5 is rubidium (Rb, Z = 37), with the electron configuration [Kr] 5s¹.
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Apply the (n + ℓ) rule to determine the filling order. For a given n, the energy of a subshell increases with n + ℓ. If two subshells have the same n + ℓ, the one with lower n fills first. For the 5th period, the relevant subshells are:
- 5s: n = 5, ℓ = 0 → n + ℓ = 5
- 4d: n = 4, ℓ = 2 → n + ℓ = 6
- 5p: n = 5, ℓ = 1 → n + ℓ = 6
Since 5s has the lowest n + ℓ (5), it fills first. Then 4d and 5p both have n + ℓ = 6, but 4d has lower n (4 < 5), so 4d fills before 5p. Thus the order is: 5s → 4d → 5p.
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Count the electrons each subshell can hold.
- 5s subshell: 1 orbital × 2 electrons = 2 electrons
- 4d subshell: 5 orbitals × 2 electrons = 10 electrons
- 5p subshell: 3 orbitals × 2 electrons = 6 electrons
Total = 2 + 10 + 6 = 18 electrons. …
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