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NCERT Exemplar · Q15

Q.(d) The electronic configuration of the element which is just above the element with atomic number 43 in the same group is ________.

(i) 1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2
(ii) 1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^3 4p^6
(iii) 1s^2 2s^2 2p^6 3s^2 3p^6 3d^6 4s^2
(iv) 1s^2 2s^2 2p^6 3s^2 3p^6 3d^7 4s^2
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The element with atomic number 43 is technetium (Tc), in group 7 of the periodic table. The element just above it in the same group is manganese (Mn, Z = 25). Its electronic configuration is 1s22s22p63s23p63d54s21s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2, which corresponds to option (A).

The key here is to understand how the periodic table is arranged and how to locate an element from its atomic number. Atomic number 43 is not a common one you memorise — but you can work it out by knowing the order of filling of orbitals and the structure of the periodic table.

The periodic table is built by filling orbitals in order of increasing energy (the Aufbau principle). Each period corresponds to the filling of a particular principal quantum shell. The s-block elements fill the left two columns, the p-block the right six, the d-block the middle ten columns (groups 3–12), and the f-block sits below.

Atomic number 43 falls in the 5th period, because by the end of the 4th period (krypton, Z = 36) we have filled up to 4p64p^6. The 5th period then starts with rubidium (Z = 37) and strontium (Z = 38), followed by the 4d transition series from yttrium (Z = 39) to cadmium (Z = 48). So Z = 43 is in the middle of that 4d series.

Counting from yttrium (Z = 39, the first 4d element):

39: Y (4d15s24d^1 5s^2), 40: Zr (4d25s24d^2 5s^2), 41: Nb (4d45s14d^4 5s^1 — an exception, but still group 5), 42: Mo (4d55s14d^5 5s^1), 43: Tc (4d55s24d^5 5s^2). So element 43 is technetium, in group 7.

Now, the element just above it in the same group is in the previous period — period 4, group 7. That element is manganese (Mn, Z = 25). Its electronic configuration is straightforward: it is the 3d transition series, period 4. Manganese has 25 electrons. Filling order: 1s22s22p63s23p64s23d51s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5. But conventionally we write the 3d before 4s when listing in order of principal quantum number: 1s22s22p63s23p63d54s21s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2.

Let's check the options:

  1. Option (A): 1s22s22p63s23p63d54s21s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2 — this is exactly manganese. Total electrons = 2+2+6+2+6+5+2=252+2+6+2+6+5+2 = 25. Correct. …

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