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NCERT Exemplar · Q27

Q.Fill in the blank: If 2x+2>0\dfrac{2}{x+2} > 0, then xx ___ −2-2.

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The inequality 2x+2>0\frac{2}{x+2} > 0 tells us the fraction is positive. Since the numerator 22 is always positive, the denominator x+2x+2 must also be positive. This gives x>−2x > -2, so the blank is filled with >.

The core idea here is simple: a fraction is positive only when its numerator and denominator have the same sign. In 2x+2\frac{2}{x+2}, the numerator is 22, a fixed positive number. So for the whole fraction to be greater than zero, the denominator x+2x+2 must also be positive.

Let’s walk through it step by step.

  1. Identify the condition for positivity

    For any real numbers aa and bb (with b≠0b \neq 0), ab>0\frac{a}{b} > 0 means aa and bb have the same sign — both positive or both negative. Here a=2>0a = 2 > 0, so we need b=x+2>0b = x+2 > 0.

  2. Solve the inequality on the denominator

    x+2>0x+2 > 0 simplifies to x>−2x > -2.

  3. Check the domain

    The original expression 2x+2\frac{2}{x+2} is undefined when x+2=0x+2 = 0, i.e., x=−2x = -2. Our solution x>−2x > -2 automatically excludes this point, so no extra restriction is needed. …

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