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NCERT Exemplar · Q41

Q.State whether the following statement is True or False: If ∣x∣≤4|x| \le 4, then x∈[−4,4]x \in [-4, 4].

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The absolute value inequality ∣x∣≤4|x| \le 4 captures all numbers whose distance from zero is at most 4, which is precisely the closed interval [−4,4][-4, 4].

Understanding absolute value inequalities

The absolute value ∣x∣|x| measures the distance of xx from zero on the number line, always returning a non-negative value. When we write ∣x∣≤4|x| \le 4, we're asking: which numbers lie within a distance of 4 units from the origin?

This geometric interpretation immediately tells us that xx can be anywhere from −4-4 to 44, including both endpoints. But let's verify this algebraically to see why the statement is true.

Step-by-step verification

1. Recall the definition of absolute value

By definition, ∣x∣=x|x| = x when x≥0x \ge 0 and ∣x∣=−x|x| = -x when x<0x < 0. This means ∣x∣|x| is the "positive version" of xx, regardless of its sign.

2. Translate the inequality ∣x∣≤4|x| \le 4

The inequality ∣x∣≤4|x| \le 4 is equivalent to saying:

−4≤x≤4-4 \le x \le 4

Why? Because if xx is positive, then ∣x∣=x≤4|x| = x \le 4 gives us x≤4x \le 4. If xx is negative, then ∣x∣=−x≤4|x| = -x \le 4, which means x≥−4x \ge -4. Combining both cases, we need xx to satisfy both conditions simultaneously.

∣x∣≤a  ⟺  −a≤x≤afor any a>0|x| \le a \iff -a \le x \le a \quad \text{for any } a > 0

3. Express in interval notation

The compound inequality −4≤x≤4-4 \le x \le 4 describes all real numbers between −4-4 and 44, including both endpoints. In interval notation, this is written as [−4,4][-4, 4]. …

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