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Physics · Ch 3 — Motion in a Plane

Position and Displacement Vectors

3.2.1

Position and Displacement Vectors

Position and Displacement Vectors

In the study of motion in a plane, we need a way to describe where an object is and how its location changes. Two vectors serve this purpose: the position vector and the displacement vector.

The Position Vector

Consider a point PP in the xx-yy plane. To specify its location, we draw a vector from the origin OO of a chosen coordinate system to the point PP. This vector is called the position vector of PP, and is denoted by r\mathbf{r}.

If the coordinates of PP are (x,y)(x, y), then the position vector is written in component form as:

r=x i^+y j^\mathbf{r} = x\,\hat{\mathbf{i}} + y\,\hat{\mathbf{j}}

where i^\hat{\mathbf{i}} and j^\hat{\mathbf{j}} are unit vectors along the xx- and yy-axes, respectively.

The magnitude of the position vector is the distance of PP from the origin:

∣r∣=x2+y2|\mathbf{r}| = \sqrt{x^{2} + y^{2}}

The direction of r\mathbf{r} is given by the angle θ\theta it makes with the positive xx-axis, measured anticlockwise:

tan⁡θ=yx\tan\theta = \frac{y}{x}

Note

The position vector depends on the choice of origin. If you shift the origin, the coordinates (x,y)(x, y) change, and so does r\mathbf{r}. This is why position is always relative.

The Displacement Vector

Now suppose the object moves from an initial point PP to a final point QQ. The displacement vector Δr\Delta\mathbf{r} is defined as the vector that points from the initial position to the final position. It tells us how far and in what direction the object has moved, regardless of the path taken.

Let the position vectors of PP and QQ be:

rP=xP i^+yP j^,rQ=xQ i^+yQ j^\mathbf{r}_{P} = x_{P}\,\hat{\mathbf{i}} + y_{P}\,\hat{\mathbf{j}}, \qquad \mathbf{r}_{Q} = x_{Q}\,\hat{\mathbf{i}} + y_{Q}\,\hat{\mathbf{j}}

Then the displacement vector is:

Δr=rQ−rP\Delta\mathbf{r} = \mathbf{r}_{Q} - \mathbf{r}_{P}

In component form:

Δr=(xQ−xP) i^+(yQ−yP) j^\Delta\mathbf{r} = (x_{Q} - x_{P})\,\hat{\mathbf{i}} + (y_{Q} - y_{P})\,\hat{\mathbf{j}}

The magnitude of the displacement is the straight-line distance between PP and QQ:

∣Δr∣=(xQ−xP)2+(yQ−yP)2|\Delta\mathbf{r}| = \sqrt{(x_{Q} - x_{P})^{2} + (y_{Q} - y_{P})^{2}}

Watch out

Displacement is not the same as distance travelled. Distance is the total length of the actual path; displacement is the straight-line separation between start and end points. For a curved path, distance is always greater than or equal to the magnitude of displacement.

Properties of Position and Displacement Vectors

The textbook lists three important properties that follow directly from the definitions.

›Proof

Property (I): The displacement vector is the difference of the final and initial position vectors.

This is the definition itself. If an object moves from PP to QQ, the change in its position is rQ−rP\mathbf{r}_{Q} - \mathbf{r}_{P}. This vector is independent of the path taken — it depends only on the endpoints.

Property (II): The displacement vector is the same for all observers, provided they use the same origin.

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Figure 3.1(a) Position and displacement vectors. (b) Displacement vector PQ and different courses of motion.
Fig. 3.1 — (a) Position and displacement vectors. (b) Displacement vector PQ and different courses of motion.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

The figure is a two-panel diagram drawn on standard xx–yy axes. In panel (a), a curved path runs from a point near the origin out into the plane. Two points on that path are labelled PP and P′P'. From the origin OO, two arrows are drawn: one to PP (labelled r\mathbf{r}) and one to P′P' (labelled r′\mathbf{r}'). A third arrow connects PP directly to P′P' — this is the displacement vector Δr=r′−r\Delta \mathbf{r} = \mathbf{r}' - \mathbf{r}. The curved path between PP and P′P' is the actual trajectory; the straight arrow is the displacement, which depends only on the start and end points, not on the path taken.

Panel (b) makes this path-independence explicit. Two fixed points are shown: PP near the bottom and QQ near the top. A straight arrow runs from PP to QQ — that is the displacement vector PQ\mathbf{PQ}. Around it, three different curved routes are drawn, passing through intermediate points labelled A,B,C,D,E,FA, B, C, D, E, F. Each route is a different physical path from PP to QQ, but the displacement arrow PQ\mathbf{PQ} is the same for all of them.

Important

The central idea is that displacement is a vector — it has both magnitude and direction, and it depends only on the initial and final positions, not on the actual path taken. This is what distinguishes displacement from distance (a scalar).

The textbook uses this figure to introduce the vector nature of displacement and to set up the definition of the displacement vector. If a particle moves from position r\mathbf{r} to position r′\mathbf{r}', the displacement vector is

Δr=r′−r\Delta \mathbf{r} = \mathbf{r}' - \mathbf{r}

where r\mathbf{r} and r′\mathbf{r}' are the position vectors of the particle at the two instants. Each position vector is drawn from the origin OO to the particle's location. The subtraction is vector subtraction: Δr\Delta \mathbf{r} is the vector that, when added to r\mathbf{r}, gives r′\mathbf{r}'.

Δr=r′−r\Delta \mathbf{r} = \mathbf{r}' - \mathbf{r} …