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NCERT Exemplar · Q71

Q.If AA is a skew symmetric matrix, then A2A^2 is a _________.

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A skew-symmetric matrix satisfies AT=−AA^T = -A. Squaring it gives A2A^2, which is symmetric because (A2)T=(−A)2=A2(A^2)^T = (-A)^2 = A^2. So A2A^2 is a symmetric matrix.

Why This Works: The Core Idea

A skew-symmetric matrix is defined by the property that its transpose equals its negative: AT=−AA^T = -A. This means that for any entry aija_{ij}, we have aij=−ajia_{ij} = -a_{ji}, and importantly, all diagonal entries must be zero (since aii=−aiia_{ii} = -a_{ii} implies aii=0a_{ii} = 0).

When you square such a matrix, something interesting happens to its symmetry. The transpose of a product reverses the order: (AB)T=BTAT(AB)^T = B^T A^T. So for A2A^2, we have (A2)T=(A⋅A)T=ATAT(A^2)^T = (A \cdot A)^T = A^T A^T. But since AT=−AA^T = -A, this becomes (−A)(−A)=A2(-A)(-A) = A^2. The two negatives cancel out, leaving the original matrix unchanged. That is the signature of a symmetric matrix.

Let's walk through this step by step.

  1. Start with the definition.

    A matrix AA is skew-symmetric if AT=−AA^T = -A. This is the only fact we need — no special properties of AA beyond this.

  2. Consider A2A^2 and take its transpose.

    We want to check whether A2A^2 is symmetric (equal to its transpose) or skew-symmetric (equal to the negative of its transpose). So compute:

(A2)T=(A⋅A)T(A^2)^T = (A \cdot A)^T

Using the rule (AB)T=BTAT(AB)^T = B^T A^T, we get:

(A2)T=ATAT(A^2)^T = A^T A^T

  1. Substitute the skew-symmetry condition. Since AT=−AA^T = -A, replace each ATA^T:

(A2)T=(−A)(−A)=(−1)(−1)⋅A⋅A=A2(A^2)^T = (-A)(-A) = (-1)(-1) \cdot A \cdot A = A^2

  1. Interpret the result. …

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