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Exercises · 4.8

Q.A closely wound solenoid 80 cm80\ \text{cm} long has 55 layers of windings of 400400 turns each. The diameter of the solenoid is 1.8 cm1.8\ \text{cm}. If the current carried is 8.0 A8.0\ \text{A}, estimate the magnitude of BB inside the solenoid near its centre.

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The magnetic field inside a long solenoid is uniform and given by B=μ0nIB = \mu_0 n I, where nn is the total number of turns per unit length. For this solenoid, n=2500 turns/mn = 2500\ \text{turns/m}, so B≈2.5×10−2 TB \approx 2.5 \times 10^{-2}\ \text{T}.

The key insight here is that a solenoid’s magnetic field near its centre depends only on the total number of turns per unit length and the current — not on the number of layers or the wire diameter, as long as the solenoid is long compared to its radius. The field lines are nearly parallel and uniform inside, so we can use the ideal solenoid formula directly.

Let’s work through it step by step.

  1. Find the total number of turns.

    The solenoid has 5 layers, each with 400 turns.

    Total turns N=5×400=2000N = 5 \times 400 = 2000 turns.

  2. Find the length of the solenoid in metres.

    Length L=80 cm=0.80 mL = 80\ \text{cm} = 0.80\ \text{m}.

  3. Calculate the number of turns per unit length nn.

n=NL=20000.80=2500 turns/mn = \frac{N}{L} = \frac{2000}{0.80} = 2500\ \text{turns/m}

  1. Apply the formula for the magnetic field inside a long solenoid. For an ideal solenoid (length >> radius), the field near the centre is:

B=μ0nIB = \mu_0 n I

where μ0=4π×10−7 T⋅m/A\mu_0 = 4\pi \times 10^{-7}\ \text{T·m/A} and I=8.0 AI = 8.0\ \text{A}.

B=μ0nIB = \mu_0 n I

  1. Plug in the numbers.

B=(4π×10−7)×2500×8.0B = (4\pi \times 10^{-7}) \times 2500 \times 8.0

First, 4π×10−7≈1.2566×10−64\pi \times 10^{-7} \approx 1.2566 \times 10^{-6}.

Then 2500×8.0=200002500 \times 8.0 = 20000.

So B≈1.2566×10−6×20000=2.5132×10−2 TB \approx 1.2566 \times 10^{-6} \times 20000 = 2.5132 \times 10^{-2}\ \text{T}.

Rounding to two significant figures (since the given data has two significant figures in current and length), we get: …

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