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Worked Examples · Example 6

Q.At what principal will the amount be ₹13,310 in 3 years at 10% per annum, compounded yearly?

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Here A=₹13,310A = ₹13{,}310, r=10%r = 10\%, t=3t = 3 years, compounded yearly. The formula A=P(1+r/100)tA = P(1+r/100)^t must be solved for PP.

Step 1 — Rearrange for PP.

P=A(1+r100)t=13,310(1.1)3P = \frac{A}{\left(1+\dfrac{r}{100}\right)^{t}} = \frac{13{,}310}{(1.1)^{3}}

Step 2 — Evaluate (1.1)3(1.1)^3. (1.1)3=1.331(1.1)^3 = 1.331.

Step 3 — Divide.

P=13,3101.331=₹10,000P = \frac{13{,}310}{1.331} = ₹10{,}000 …

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