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Worked Examples · Example 2

Q.A sum of ₹8,000 is invested at 10% per annum, compounded half-yearly, for 1 year 6 months. Find the amount and the compound interest.

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Here P=₹8,000P = ₹8{,}000, annual rate r=10%r = 10\%, time t=1t = 1 year 6 months =1.5= 1.5 years, compounded half-yearly.

Step 1 — Convert to half-yearly terms. Number of half-year periods =2t=2×1.5=3= 2t = 2 \times 1.5 = 3. Rate per half-year =r2=102=5%= \dfrac{r}{2} = \dfrac{10}{2} = 5\%.

Step 2 — Apply the half-yearly formula.

A=P(1+r200)2t=8,000(1+10200)3=8,000(1.05)3A = P\left(1+\frac{r}{200}\right)^{2t} = 8{,}000\left(1+\frac{10}{200}\right)^{3} = 8{,}000(1.05)^{3}

Step 3 — Evaluate. (1.05)3=1.157625(1.05)^3 = 1.157625, so

A=8,000×1.157625=₹9,261A = 8{,}000 \times 1.157625 = ₹9{,}261

Step 4 — Compound interest.

CI=A−P=9,261−8,000=₹1,261CI = A - P = 9{,}261 - 8{,}000 = ₹1{,}261

✓Final answer

Amount =₹9,261= ₹9{,}261; compound interest =₹1,261= ₹1{,}261.

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