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Worked Examples · Example 6

Q.Simplify: sin⁡(90°−θ)⋅sec⁡θ\sin(90°-\theta)\cdot\sec\theta.

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Step 1 — apply the complementary-angle relation.

sin⁡(90°−θ)=cos⁡θ\sin(90°-\theta)=\cos\theta

Step 2 — substitute.

sin⁡(90°−θ)⋅sec⁡θ=cos⁡θ⋅sec⁡θ\sin(90°-\theta)\cdot\sec\theta = \cos\theta\cdot\sec\theta …

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