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Example · Example 23

Q.A gas is collected over water at 25∘C25^\circ\text{C}; the total pressure of the moist gas is 750 mmHg750\ \text{mmHg}. If the vapour pressure of water at 25∘C25^\circ\text{C} is 23.8 mmHg23.8\ \text{mmHg}, find the pressure of the dry gas.

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When a gas is collected over water, the gas in the collection vessel is always "wet" — mixed with water vapour that evaporates from the liquid surface — so the measured total pressure is the sum of the dry gas's partial pressure and water's vapour pressure at that temperature, by Dalton's law: Ptotal=Pdry gas+Pwater vapourP_{\text{total}} = P_{\text{dry gas}} + P_{\text{water vapour}}. Rearranging: Pdry gas=Ptotal−Pwater vapourP_{\text{dry gas}} = P_{\text{total}} - P_{\text{water vapour}}. Substituting the given values: Pdry gas=750−23.8=726.2 mmHgP_{\text{dry gas}} = 750 - 23.8 = 726.2\ \text{mmHg}. This correction must always be applied before using the collected gas's pressure in any subseq …

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