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Q.Find the principal amplitude of (-1-i).

West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018Subjective· 2mImportance★★★★★est
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−1−i-1-i lies in the third quadrant with reference angle π/4\pi/4; the principal argument (in (−π,π](-\pi,\pi]) is −3π/4-3\pi/4.

For z=−1−iz=-1-i, both the real part (−1)(-1) and imaginary part (−1)(-1) are negative, so zz lies in the third quadrant.

The reference angle is tan⁡−1(∣−1∣∣−1∣)=tan⁡−1(1)=π4\tan^{-1}\left(\dfrac{|-1|}{|-1|}\right)=\tan^{-1}(1)=\dfrac{\pi}{4}.

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