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Exercise: Modulus and Argand Plane · Q16

Q.Find the modulus and the argument of z=4iz=4i.

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z=4iz=4i has a=0, b=4a=0,\ b=4, so ∣z∣=02+42=4|z|=\sqrt{0^2+4^2}=4. Since a=0a=0 and b>0b>0, the point lies exactly on the positive imaginary axis, so θ=π2\theta=\dfrac{\pi}{2} (no quadrant correction needed — this is one of the axis cases). Check: $4\left(\cos\dfr …

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