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Q.Value of ω^n + ω^2n, where ω = (-1+i√3)/2 and n = 3k+1, is

(a) 0
(b) -1
(c) 1
(d) None of these.
West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018MCQ· 1mImportance★★★★★est
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ω\omega is a primitive cube root of unity, so ωn+ω2n\omega^n+\omega^{2n} reduces to ω+ω2=−1\omega+\omega^2=-1 whenever n=3k+1n=3k+1.

Here ω=−1+i32\omega=\dfrac{-1+i\sqrt3}{2} is a complex cube root of unity, satisfying ω3=1\omega^3=1 and 1+ω+ω2=01+\omega+\omega^2=0.

Since n=3k+1n=3k+1:

ωn=ω3k+1=(ω3)k⋅ω=1k⋅ω=ω\omega^n=\omega^{3k+1}=(\omega^3)^k\cdot\omega=1^k\cdot\omega=\omega …

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