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Exercise: Algebra of Complex Numbers · Q9

Q.Find the multiplicative inverse of z=2+3iz=2+3i.

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For z=2+3iz=2+3i: ∣z∣2=22+32=4+9=13|z|^2=2^2+3^2=4+9=13. So z−1=zˉ∣z∣2=2−3i13=213−313iz^{-1}=\dfrac{\bar z}{|z|^2}=\dfrac{2-3i}{13}=\dfrac2{13}-\dfrac3{13}i. Check: $(2+3i)\left(\dfrac2{13}-\dfrac3{13}i\right)=\dfrac{4-6i …

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