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Exercise: Hyperbola · Q28

Q.Find the equation of the hyperbola whose foci are (±13,0)(\pm13,0) and the length of the transverse axis is 2424.

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The transverse axis has length 2424, so 2a=24⇒a=122a=24\Rightarrow a=12. The foci (±13,0)(\pm13,0) give c=13c=13.

b2=c2−a2=169−144=25.b^2=c^2-a^2=169-144=25. …

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