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Exercise: Hyperbola · Q30

Q.Find the equation of the hyperbola whose foci are (±13,0)(\pm13,0) and the length of the conjugate axis is 2424.

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The conjugate axis has length 2424, so 2b=24⇒b=122b=24\Rightarrow b=12. The foci (±13,0)(\pm13,0) give c=13c=13.

a2=c2−b2=169−144=25.a^2=c^2-b^2=169-144=25. …

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