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Example · Example 5

Q.Let U={1,2,3,…,10}U = \{1, 2, 3, \dots, 10\}, A={1,2,3,4,5}A = \{1, 2, 3, 4, 5\} and B={4,5,6,7,8}B = \{4, 5, 6, 7, 8\}. Find A∪BA \cup B, A∩BA \cap B, A−BA - B, B−AB - A, A′A', and verify that (A∪B)′=A′∩B′(A \cup B)' = A' \cap B'.

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With U={1,…,10}U=\{1,\dots,10\}, A={1,2,3,4,5}A=\{1,2,3,4,5\}, B={4,5,6,7,8}B=\{4,5,6,7,8\}: A∪B={1,2,3,4,5,6,7,8}A \cup B = \{1,2,3,4,5,6,7,8\} (every element in at least one set); A∩B={4,5}A \cap B = \{4,5\} (common to both); A−B={1,2,3}A - B = \{1,2,3\} (in AA, not in BB); B−A={6,7,8}B - A = \{6,7,8\} (in BB, not in AA); A′=U−A={6,7,8,9,10}A' = U - A = \{6,7,8,9,10\}. Also B′=U−B={1,2,3,9,10}B' = U - B = \{1,2,3,9,10\}. Now (A∪B)′=U−{1,…,8}={9,10}(A \cup B)' = U - \{1,\dots,8\} = \{9,10\} …

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