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Mathematics · Ch 11 — Straight Lines

Point-Slope Form

5

Point-Slope Form

Every remaining form in this chapter is really just a special case, or a short consequence, of the single idea in this section: fixing one point and the slope pins down a line completely, and its equation follows directly from the definition of slope itself.

Setting up. Suppose a (non-vertical) line has slope mm and passes through a known, fixed point (x1,y1)(x_1,y_1). Let P(x,y)P(x,y) be any other point on the line — (x,y)(x,y) stands for a completely general point, and the equation sought is the algebraic condition (x,y)(x,y) must satisfy to lie on this particular line.

Derivation. Since (x1,y1)(x_1,y_1) and (x,y)(x,y) are two points on the same line, the slope computed between them must equal the line's given slope mm (Section 2):

y−y1x−x1=m,x≠x1.\frac{y-y_1}{x-x_1} = m, \qquad x \ne x_1.

Multiplying both sides by (x−x1)(x-x_1) clears the fraction and gives the point-slope form:

y−y1=m(x−x1).\boxed{y - y_1 = m(x-x_1)}.

This single equation is satisfied by every point on the line and by no point off it, because it says exactly "the slope from (x1,y1)(x_1,y_1) to (x,y)(x,y) is mm" — true only for points on the line through (x1,y1)(x_1,y_1) with that slope.

Why this is the most fundamental form. Every other equation of a line used in this chapter — slope-intercept, two-point, intercept — is obtained from the point-slope form by choosing a convenient point (the y-intercept, one of two given points, an axis intercept) and substituting it in. None of them contains any new geometric idea beyond this one. …