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Mathematics · Ch 11 — Straight Lines

Two-Point Form

7

Two-Point Form

Frequently a line is described not by a point and a slope but by two points it passes through; this section shows the slope-then-point-slope route that handles this case in two short steps.

Setting up. Let (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) be two distinct given points on a line, with x1≠x2x_1\ne x_2 (so the line is not parallel to the y-axis — that case is handled directly by Section 4).

Step 1 — find the slope. By the slope formula of Section 2,

m=y2−y1x2−x1.m = \frac{y_2-y_1}{x_2-x_1}.

Step 2 — substitute into the point-slope form. Using (x1,y1)(x_1,y_1) as the fixed point in the point-slope form of Section 5,

y−y1=y2−y1x2−x1(x−x1).y - y_1 = \frac{y_2-y_1}{x_2-x_1}(x-x_1).

This is the two-point form. It is equally written in the more symmetric layout

y−y1y2−y1=x−x1x2−x1\boxed{\frac{y-y_1}{y_2-y_1} = \frac{x-x_1}{x_2-x_1}}

by dividing both sides by y2−y1y_2-y_1 (when y2≠y1y_2\ne y_1) — a form making the symmetry between the two given points visually clear, since swapping the labels 1↔21\leftrightarrow2 throughout leaves the equation unchanged.

Why the choice of which point to substitute doesn't matter. Using (x2,y2)(x_2,y_2) instead of (x1,y1)(x_1,y_1) as the fixed point in Step 2 gives y−y2=m(x−x2)y-y_2=m(x-x_2); expanding both versions shows they simplify to the same general equation Ax+By+C=0Ax+By+C=0, since both describe the one line already pinned down uniquely by two points. …