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Exercise: Angle Measurement · Q11

Q.The angles of a triangle are in the ratio 3:4:53:4:5. Find the smallest angle in radian measure.

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Let the angles be 3k,4k,5k3k,4k,5k. Since the angle sum of a triangle is 180∘180^\circ,

3k+4k+5k=180∘⇒12k=180∘⇒k=15∘3k+4k+5k=180^\circ \Rightarrow 12k=180^\circ \Rightarrow k=15^\circ. The smallest angle is …

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