Skip to content
Exercise: Trigonometric Identities · Q12

Q.Determine the quadrant in which θ=5π3\theta = \dfrac{5\pi}{3} (0≤θ<2π0 \le \theta < 2\pi, measured from the positive x-axis) lies, and state the sign of sin⁡θ\sin\theta, cos⁡θ\cos\theta and tan⁡θ\tan\theta there.

West Bengal WbchseTextbookSubjectiveImportance★★★★★est
44% · 14/32 Questions
✓ Free question

Concept understanding — Trigonometric Functions in Quadrants

Trigonometric Functions in Quadrants

Imagine standing at the centre of a circle, facing east. If you turn by some angle, you end up pointing in a certain direction. That direction has both a horizontal component (east-west) and a vertical component (north-south). Trigonometric functions are just a way to describe those components — and whether they are positive or negative depends entirely on which quadrant you're facing.

The Four Quadrants

The coordinate plane is split into four quadrants, numbered anticlockwise starting from the top-right:

  • Quadrant I (0° to 90°): x > 0, y > 0
  • Quadrant II (90° to 180°): x < 0, y > 0
  • Quadrant III (180° to 270°): x < 0, y < 0
  • Quadrant IV (270° to 360°): x > 0, y < 0

Now, recall the definitions on the unit circle (radius = 1):

  • cos⁡θ\cos \theta = x-coordinate of the point on the circle
  • sin⁡θ\sin \theta = y-coordinate of that point
  • tan⁡θ=sin⁡θcos⁡θ\tan \theta = \frac{\sin \theta}{\cos \theta}

So the sign of cos⁡θ\cos \theta follows the sign of x, and the sign of sin⁡θ\sin \theta follows the sign of y. That's all there is to it.

The Sign Pattern

Quadrantsin⁡θ\sin \thetacos⁡θ\cos \thetatan⁡θ\tan \theta
I (0–90)+++
II (90–180)+––
III (180–270)––+
IV (270–360)–+–
Tip

The mnemonic "All Students Take Coffee" helps you remember which functions are positive in each quadrant, starting from QI and going anticlockwise: All (all positive), Sine (sin positive), Tan (tan positive), Cos (cos positive).

Why This Matters

Suppose you're solving sin⁡θ=12\sin \theta = \frac{1}{2}. The calculator gives you θ=30∘\theta = 30^\circ, but that's only one solution. Because sine is positive in both QI and QII, there's a second angle: 180∘−30∘=150∘180^\circ - 30^\circ = 150^\circ. If you forget the quadrant rule, you lose half the answers.

Similarly, if cos⁡θ=−32\cos \theta = -\frac{\sqrt{3}}{2}, cosine is negative in QII and QIII. So the solutions are 150∘150^\circ and 210∘210^\circ (plus full rotations).

Watch out

Never assume an angle from a calculator is the only one. Always check which quadrants match the sign of the given trigonometric value.

The Core Idea in One Sentence

Important

The sign of a trigonometric function is determined by the quadrant in which the terminal side of the angle lies — sine follows y, cosine follows x, and tangent follows their ratio.

Once you internalise that, you can find any angle, any sign, anywhere on the circle.

The sign of trigonometric functions in each quadrant is a core rule from the NCERT Class 11 Mathematics chapter on Trigonometric Functions, and "ASTC rule trigonometry all students take coffee" is a widely searched mnemonic-based topic for CBSE board and JEE Main/NEET revision. Correctly applying quadrant signs to find all solutions of a trigonometric equation is also one of the most commonly tested skills in "trigonometry important questions" for competitive exams.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.