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Physics · Ch 3 — Motion in a Plane

Vector (Cross) Product of Two Vectors

3.9

Vector (Cross) Product of Two Vectors

The second way of multiplying two vectors, the vector product (or cross product), of

A⃗\vec A and B⃗\vec B is defined as

A⃗×B⃗=ABsin⁡θ n^,\vec A \times \vec B = AB\sin\theta\,\hat n,

where θ\theta is the angle between A⃗\vec A and B⃗\vec B, and n^\hat n is a unit vector

perpendicular to the plane containing both A⃗\vec A and B⃗\vec B. Unlike the dot product,

the result of a cross product is itself a vector.

Direction — the right-hand rule. The direction of n^\hat n (and hence of

A⃗×B⃗\vec A \times \vec B) is found by curling the fingers of the right hand from A⃗\vec A

towards B⃗\vec B through the smaller angle θ\theta between them; the extended thumb then

points along A⃗×B⃗\vec A \times \vec B (see the figure). Because of this rule, the cross

product is anticommutative: reversing the order of multiplication reverses the direction

of the result, A⃗×B⃗=−(B⃗×A⃗)\vec A \times \vec B = -(\vec B \times \vec A).

Geometric meaning. The magnitude ∣A⃗×B⃗∣=ABsin⁡θ|\vec A \times \vec B| = AB\sin\theta is numerically

equal to the area of the parallelogram formed by A⃗\vec A and B⃗\vec B as its two adjacent

sides (base ×\times height, with Bsin⁡θB\sin\theta as the perpendicular height).

Component formula. For two vectors lying entirely in the xy-plane,

A⃗=Axi^+Ayj^\vec A = A_x\hat i + A_y\hat j and B⃗=Bxi^+Byj^\vec B = B_x\hat i + B_y\hat j, the cross product has

only a z-component (perpendicular to the plane), given by

A⃗×B⃗=(AxBy−AyBx) k^.\vec A \times \vec B = (A_xB_y - A_yB_x)\,\hat k.

Special cases. When A⃗\vec A and B⃗\vec B are parallel (θ=0∘\theta = 0^\circ), the cross

product is zero (no parallelogram area is enclosed). When they are perpendicular

(θ=90∘\theta = 90^\circ), the magnitude is at its maximum, ABAB. Physical applications: …

Figure 1Right-hand rule for the vector (cross) product

What this figure shows. A right-hand-rule illustration for the vector (cross) product of two vectors vec A and vec B lying in a plane, with the angle theta between them marked at their common tail. The right hand is drawn with its fingers curling from vec A towards vec B through the smaller angle theta, and the extended thumb points along the direction of the resultant vector vec C = vec A x vec B, which is perpendicular to the plane containing vec A and vec B. A dashed parallelogram is also shown spanning vec A and vec B, with its enclosed area shaded, illustrating that the magnitude |vec A x vec B| = A B sin(theta) equal …